上次因为要编写自动登录邮箱的程序，需要Base64编码，但是我看了几种版本的VB下Base64编码的程序，发现要么就是太冗长，要么就是不支持中文，要么根本不能用，于是我想求人不如求己，便仔细研究了一下Base64编码原理，然后编写了这段程序，在电脑上调试通过，可以顺利进行Base64编码/解码，速度也快。

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程序模块：

Option Explicit
Private Const cstBase64 = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"
Private arrBase64() As String
'作者:同济黄正 引用请注明出处:http://hz932.ys168.com
'00100001 00100001 00100001             --源码
'00001000 00010010 00000100 00100001    --Base64码

Public Function Base64Encode(strSource As String) As String
On Error Resume Next
'适用于中、英文的Base64编码/解码VB6超精简版 作者:同济黄正 引用请注明出处:http://hz932.ys168.com
If UBound(arrBase64) = -1 Then
    arrBase64 = Split(StrConv(cstBase64, vbUnicode), vbNullChar)
End If
Dim arrB() As Byte, bTmp(2)  As Byte, bT As Byte
Dim I As Long, J As Long
arrB = StrConv(strSource, vbFromUnicode)

J = UBound(arrB)
For I = 0 To J Step 3
    Erase bTmp
    bTmp(0) = arrB(I + 0)
    bTmp(1) = arrB(I + 1)
    bTmp(2) = arrB(I + 2)
   
    bT = (bTmp(0) And 252) / 4
    Base64Encode = Base64Encode & arrBase64(bT)
   
    bT = (bTmp(0) And 3) * 16
    bT = bT + bTmp(1) \ 16
    Base64Encode = Base64Encode & arrBase64(bT)
   
    bT = (bTmp(1) And 15) * 4
    bT = bT + bTmp(2) \ 64
    If I + 1 <= J Then
        Base64Encode = Base64Encode & arrBase64(bT)
    Else
        Base64Encode = Base64Encode & "="
    End If
   
    bT = bTmp(2) And 63
    If I + 2 <= J Then
        Base64Encode = Base64Encode & arrBase64(bT)
    Else
        Base64Encode = Base64Encode & "="
    End If
Next
End Function

Public Function Base64Decode(strEncoded As String) As String
'适用于中、英文的Base64编码/解码VB6超精简版 作者:同济黄正 引用请注明出处:http://hz932.ys168.com
On Error Resume Next
Dim arrB() As Byte, bTmp(3)  As Byte, bT, bRet() As Byte
Dim I As Long, J As Long
arrB = StrConv(strEncoded, vbFromUnicode)
J = InStr(strEncoded & "=", "=") - 2
ReDim bRet(J - J \ 4 - 1)
For I = 0 To J Step 4
    Erase bTmp
    bTmp(0) = (InStr(cstBase64, Chr(arrB(I))) - 1) And 63
    bTmp(1) = (InStr(cstBase64, Chr(arrB(I + 1))) - 1) And 63
    bTmp(2) = (InStr(cstBase64, Chr(arrB(I + 2))) - 1) And 63
    bTmp(3) = (InStr(cstBase64, Chr(arrB(I + 3))) - 1) And 63
   
    bT = bTmp(0) * 2 ^ 18 + bTmp(1) * 2 ^ 12 + bTmp(2) * 2 ^ 6 + bTmp(3)
   
    bRet((I \ 4) * 3) = bT \ 65536
    bRet((I \ 4) * 3 + 1) = (bT And 65280) \ 256
    bRet((I \ 4) * 3 + 2) = bT And 255
Next
Base64Decode = StrConv(bRet, vbUnicode)
End Function

 

本文来源：http://blog.csdn.net/hz932/archive/2007/08/29/1764271.aspx